has_many :thoughts: Colin's Ruby Quiz #126 Submission

Colin's Ruby Quiz #126 Submission

Colin A. Bartlett — Sun, 03 Jun 2007 09:03:00 -0400

If you haven’t looked at this week’s RubyQuiz yet, beware. Spoilers ahead.

This week’s quiz was dead simple. But I think that’s the point of this one. The most interesting thing about RubyQuiz for me is looking at how other people solved the same problem (no matter how simple) and learning about other ways to do things.

Here’s my solution:

(1..100).each do |n|
  ret = ""
  ret += "Fizz" if n.divmod(3).last == 0
  ret += "Buzz" if n.divmod(5).last == 0
  ret = n if ret == ""
  puts ret
end

The challenge presented this week is one that is well suited for a quick in-interview coding session for potential hires. Having prospective employees write code was a new idea to me that I read about in Joel on Software. And although I didn’t have candidates in the last round of hiring write code, I did review some psudo-code on the whiteboard with them and I think the next candidates will actually sit down at a machine and tap something out for us in our presence.

"Colin's Ruby Quiz #126 Submission" by Mat Schaffer

Sun, 03 Jun 2007 16:46:56 -0400

I like this one much better:

1.upto(?d){|i,x|i%3<1&&x=:Fizz;puts i%5<1?"#{x}Buzz":x||i}

courtesy of
http://blade.nagaokaut.ac.jp/cgi-bin/scat.rb/ruby/ruby-talk/241505

(No I don't really think you should do this in an interview, but I love the absurdity of it :) ).

"Colin's Ruby Quiz #126 Submission" by AlSquire

Sun, 03 Jun 2007 12:05:42 -0400

A one line and not very readable way :

puts (1..100).map { |i| (ret = { "Fizz" => 3, "Buzz" => 5 }.map
 { |w, m| w if i % m == 0 }.join) == "" ? i : ret }

"Colin's Ruby Quiz #126 Submission" by AlSquire

Sun, 03 Jun 2007 11:28:27 -0400

I would have used the % operator for modulo ( if n % 3 == 0 ).